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2 years ago

Select all names that apply. 121 121

Mathematics

1 answer:

Naily [24]2 years ago

8 0

I don't understand the question

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A bag contains 5 2/5kg of sand. The bag has a hole in it. Every 10 minutes, 1 2/3kg of sand escapes from the bag. After 20 minut

fenix001 [56]

Quantify of sand in a bag =

$= \: 5 \frac{2}{5} \ \:$

$= \frac{(5 \times 5 +2) }{5}$

$= \frac{27}{5} \: kg$

Quantity of sand that escapes in every 10 minutes :-

$= 1 \frac{2}{3} kg$

Quantity of sand that will escape in 20 minutes :-

$= 1 \frac{2}{3} \times 2$

$= \frac{(3 \times 1 + 2)}{3} \times 2$

$= \frac{5}{3} \times 2$

$= \frac{10}{3}$

Quantity of sand that will remain in the sand bag :-

$= \frac{27}{5} - \frac{10}{3}$

$= \frac{(27 \times 3)}{15} - \frac{(10 \times 5)}{15}$

$= \frac{81}{15} - \frac{50}{15}$

$= \frac{31}{15}$

$= 2 \frac{1}{5} \: kg$

$therefore \: , \: 2 \frac{1}{5} \: kg \: sand \: is \: left \: in \: the \: bag \: .$

3 0

2 years ago

Simplify there is a picture

kicyunya [14]

2 to the power of 20/3 to the power of 8. 2^20/3^8 for short.

5 0

2 years ago

james is stocking shelves with notebooks. if he has 5 different notebooks, in how many ways can he arrange them on a shelf?

nadya68 [22]

Answer: 120

Step-by-step explanation: I got it right, hope this helps ✨

6 0

2 years ago

Read 2 more answers

Find the rate of change: Mike can bike 3 miles in an hour. What is the speed at which mike can bike?

masya89 [10]

Rate of change=change in y divided by change in x
y= 3,6,9
x= 1,2,3
The numbers chosen above are because if mike travels 3 miles in one hours then he can travel 6 miles in two hours and 9 miles in 3 hours.
Change in y = 3
Change in x = 1
3 / 1 = 3
So, the rate of change is 3.

3 0

2 years ago

Don’t save the answer and I really need help

Ksju [112]

9514 1404 393

Answer:

zero solutions

Step-by-step explanation:

The first inequality has a boundary line with a slope of 3 and a y-intercept of 9. Shading is above the boundary line.

The second inequality has a parallel boundary line with a slope of 3 and a y-intercept somewhat lower, at -1. Shading is below this boundary line.

There is a gap between the shaded areas, so no points will be solutions to both inequalities.

3 0

2 years ago