the slope of the perpendicular line to the line through the two points is 0
Answer:
The distribution is
Solution:
As per the question:
Total no. of riders = n
Now, suppose the is the time between the departure of the rider i - 1 and i from the cable car.
where
= independent exponential random variable whose rate is
The general form is given by:
(a) Now, the time distribution of the last rider is given as the sum total of the time of each rider:
Now, the sum of the exponential random variable with with rate is given by:
To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
Answer:
1) Subtracting one from the other
2) x = 0.375 and y = 0.125
Step-by-step explanation:
Equation 1 :
Equation 2:
To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,
Now for the second equation:
Now subtracting equation 2 from equation 1
now insert this value of y into any equation
lets insert it into equation 1
Answer:
225 m²
Step-by-step explanation:
If W is the width of the rectangle, and L is the length, then:
60 = 2W + 2L
A = WL
Use the first equation to solve for one of the variables:
30 = W + L
L = 30 − W
Substitute into the second equation:
A = W (30 − W)
A = 30W − W²
This is a parabola, so we can find the vertex using the formula x = -b/(2a).
W = -30 / (2 × -1)
W = 15
Or, we can use calculus:
dA/dW = 30 − 2W
0 = 30 − 2W
W = 15
Solving for L:
L = 30 − W
L = 15
So the maximum area is:
A = WL
A = (15)(15)
A = 225