2 years ago

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Mathematics

1 answer:

vlabodo [156]2 years ago

7 0

Answer: 108

Step-by-step explanation:

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AfilCa [17]

Answer:

Step-by-step explanation:

90-47=43

4 0

3 years ago

What is the area of this regular pentagon that has been divided into five congruent triangles?

Len [333]

Answer:

120 cm^2.

Step-by-step explanation:

The area of one triangle = 1/2 * base * height

= 1/2 * 8 * 6

= 1/2 * 48

= 24 cm^2

So area of the pentagon = 5 * 24

= 120 cm^2.

7 0

2 years ago

Stu counted the lines of a page in his book. Counting by three gave a remainder of 2, counting by fives also gave a remainder of

nirvana33 [79]

47

6*7=42
15*3=45
9*5=45

6 0

2 years ago

Can somebody help me with this problem

soldier1979 [14.2K]

115 degrees because there are 180 degrees in a triangle so let the missing angle in the trinagle be x. Then we have x+75+40=180. Solving for x and subtracting that from 180 (supplementary angles) we get 115 degrees.

4 0

3 years ago

In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the

Sidana [21]

Step 1

Find the value of TS

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

$\frac{TR}{TP} =\frac{TS}{QT}$

solve for TS

$TS =\frac{TR*QT}{TP}$

we have

$RP=2\ cm\\TP=18\ cm\\QT=27\ cm$

$TR=TP+RP\\TR=18+2=20\ cm$

substitute

$TS =\frac{20*27}{18}$

$TS =30\ cm$

Step 2

Find the value of SQ

we know that

$SQ=TS-QT$

we have

$TS =30\ cm$

$QT=27\ cm$

substitute

$SQ=30\ cm-27\ cm=3\ cm$

therefore

the answer is

the value of SQ is $3\ cm$

6 0

2 years ago

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