Answer:
what is the question, true or false?
Step-by-step explanation:
No, you should have reduced each base to...
3^(3*2x) = 3^(2*(x-3))
and then you can cancel each base
3*2x = 2*(x-3)
6x = 2x-6
4x= -6
x = -3/2
Answer:
No real
solution
Step-by-step explanation:
Firstly, let us check if we would be having a real solution
We start by rewriting the equation
We have this as;
8x^2 -25x + 24 = 0
We proceed to get the discriminant
Mathematically, we have this as;
D = b^2 - 4ac
b is the coefficient of x which is -25
a is the coefficient of x^2 which is 8
c is the last number which is 24
So we have;
D = (-25)^2 - 4(8)(24)
D = 625 - 768 = -143
Since the value of the discriminant is negative, there cannot be real roots
What we have as solution are complex roots
For any equation with more than one variable, there is either no solution or infinitely many solutions.
If we can find just <em>one</em> solution that works, that would eliminate the possibility of there being no solution, and so we could prove it to have infinitely many solutions.
Can we come up with at least one solution to these equations? Of course!
For x=y
Thinking of two equal numbers is extremely easy. For instance, if we chose x to be 2 and y to be 2, that's a solution right there! Thus x=y has infinitely many solutions.
It's just as easy picking two numbers that are equal when you multiply them by 1.25. Think back to the multiplication property of equality. If two things are equal, and you multiply them by a number, they will still be equal. So all we need is, once again, two equal numbers. 2 and 2, boom and boom. 1.25x=1.25y has infinitely many solutions as well.
