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3 years ago

What is (3⁴×5⁴)-³ =?

Mathematics

1 answer:

Kay [80]3 years ago

7 0

Answer:

The solution to the given expression is 1/2562890625

Step-by-step explanation:

(3⁴ × 5⁴)⁻²

Simplify the terms inside the parentheses. 3⁴ × 5⁴ is the same as 15⁴ because even though the base numbers are different, the exponents are the same which makes it similar.

(15⁴)⁻²

Now, for this step, we are going to add the exponents because when multiplying, the exponential numbers add together. So 4 × -2 = -8.

15⁻⁸

Since we can not have a negative exponent, we are going to change this into a fraction. We do this by putting this term in a fraction where 1 is the numerator and the term is the denominator.

1 / 15⁻⁸

Now, we simplify the term on the bottom.

1 / 2562890625

So, this is the solution to the problem.

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-9x + 15 = -48 ?????????????????????/

Komok [63]

Answer:

x=7

Step-by-step explanation:

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3 years ago

A migrating bird flies 576 miles in 16 hours.How many miles does it fly in 3 hours

user100 [1]

Answer: It flies 108 miles in 3 hours.

Step-by-step explanation:

576/16 = 36

It flies 36 miles per hour

36 * 3 = 108

7 0

3 years ago

The resting heart rate for an adult horse should average about µ = 47 beats per minute with a (95% of data) range from 19 to 75

KatRina [158]

Answer:

a. 0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. 0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. 0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean:

$\mu = 47$

(95% of data) range from 19 to 75 beats per minute.

This means that between 19 and 75, by the Empirical Rule, there are 4 standard deviations. So

$4\sigma = 75 - 19$

$4\sigma = 56$

$\sigma = \frac{56}{4} = 14$

a. What is the probability that the heart rate is less than 25 beats per minute?

This is the p-value of Z when X = 25. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 47}{14}$

$Z = -1.57$

$Z = -1.57$ has a p-value of 0.0582.

0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. What is the probability that the heart rate is greater than 60 beats per minute?

This is 1 subtracted by the p-value of Z when X = 60. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 47}{14}$

$Z = 0.93$

$Z = 0.93$ has a p-value of 0.8238.

1 - 0.8238 = 0.1762

0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. What is the probability that the heart rate is between 25 and 60 beats per minute?

This is the p-value of Z when X = 60 subtracted by the p-value of Z when X = 25. From the previous two items, we have these two p-values. So

0.8238 - 0.0582 = 0.7656

0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

3 0

3 years ago

Ali ran 3/10 km before school after school she ran 1/5 km

miss Akunina [59]

Answer:

1/2 km

Step-by-step explanation:

3/10 + 1/5, find common denominators

3/10 + 2/10 = 5/10, simplify

1/2 km

8 0

3 years ago

The slope of AB is 3 over 4 and point A is (2. 9). How many possible locations are there for point

nignag [31]

Answer:

Part 1) There are infinity locations for the point B

Part 2) see the explanation

Step-by-step explanation:

Part 1) How many possible locations are there for point B?

we know that

The equation of a line in point slope form is equal to

$y-y1=m(x-x1)$

where

$m=\frac{3}{4}$

$(x1,y1)=(2,9)$

substitute

$y-9=\frac{3}{4}(x-2)$

Convert to slope intercept form

$y-9=\frac{3}{4}x-\frac{6}{4}$

$y=\frac{3}{4}x-\frac{6}{4}+9$

$y=\frac{3}{4}x+\frac{30}{4}$

$y=0.75x+7.5$

Point B can be any point ( different from point A) that satisfies the linear equation

therefore

There are infinity locations for the point B

Part 2) Describes a method to location the point

To locate the point, one of the two coordinates must be known. The known coordinate is placed into the linear equation and the equation is solved to find the value of the missing coordinate

Example

Suppose that the x-coordinate of point B is 4

For x=4

substitute in the linear equation

$y=0.75(4)+7.5=10.5$

The coordinates of point B is (4,10.5)

3 0

3 years ago

What is (3⁴×5⁴)-³ =?​

What is (3⁴×5⁴)-³ =?