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Evgen [1.6K]
3 years ago
5

What is the IQR (Inter Quartile Range) for the data set?

Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0
Arrange in ascending order:-

6 7 11 13 14 15 15 19 21


median = 14 
lower quartile  =  mean of 7 and 11 = 9
upper quatile =   mean of 15 and 19 = 17 

Interquartile range = 17 - 9 = 8

answer is 8

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It takes Alexandra 2 hours and 44 minutes to cut the grass. Austin needs 3 hours and 14 minutes to cut the grass. If they work t
Vedmedyk [2.9K]
For problems such as this, it can be handy to remember that
.. 1/(1/a +1/b) = ab/(a +b)

The time required to do a job is the inverse of the rate at which the job is done. Rates are added when people work together (in math problems, not in real life).

(2:44)*(3:14)/(2:44 +3:14) = 1:28:52.3

___
2:44 = 41/15 hours = 82/30 hours
3:14 = 97/30 hours
Using the formula above, we have a "working together" time of
.. (82/30)*(97/30)/(82/30 +97/30) = 82*97/(30*179) = 3977/2685 . . . hours
.. = 1 hour 28 156/179 minutes
.. = 1 hour 28 minutes 52 52/179 seconds

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Learn to use the fraction functions on your calculator. They can be very helpful.
6 0
3 years ago
What is 3 days 8 hours and 15 minutes plus 2 days 15 hours and 45 minutes?
kondaur [170]
A Total of 6 Days!

Cheers:D
7 0
3 years ago
HELP!! Not hard, just confusing.. ΔABC is reflected across the x-axis and then translated 4 units up to create ΔA′B′C′. What are
allsm [11]
The coordinates of the vertices of ΔABC are:A( x1, y1), B( x2, y2) and C( x3, y 3 ). After it is reflected across the x-axis, coordinates are ( x1, -y1), (x2, -y2), (x3, -y3). Finally, the coordinates of the vertices of ΔA´B´C´ after translation are: A´( x1, 4-y1), B´( x2, 4- y2), C´( x3, 4-y3 ) 
8 0
3 years ago
If mn = 16 and m^2 + n^2 = 68 then (m+n)^2 =
Dima020 [189]

Answer:

B.   100

Step-by-step explanation:

(m + n)^2

= m^2 + 2mn + n^2

Rearrange

(m^2 + n^2) + 2mn

Substitute

(68) + 2*16

= 68 + 32

= 100

7 0
3 years ago
Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
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