75.89 + 0.12x = 27.41 + 0.36x
75.89 - 27.41 = 0.24x
48.48 = 0.24x
x = 48.48 / 0.24
x = 202
Each sent 202 text messages
Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :

For a square , 
⇒ 
⇒ 
⇒ 
⇒ 
Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Answer:

Step-by-step explanation:
Using the rules of exponents
×
=
,
= 1
m² ×
× 
=
× 
=
× 
= 1 × 
= 
Answer:
?????
Step-by-step explanation:
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