Answer:
a. Diego
b. Lin
Step-by-step explanation:
a. Diego
b. Lin
It's pretty easy just do some subtraction.
Actually look and pay attention in class this is like grade 1 math.
Answer:
∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG
Step-by-step explanation:
We have that the initial triangles are equal. Let us check which components remain within the final triangles as the same. The only such components are the angles B and C. We now know that we have to apply a triangle equality criterion.
The triangles BGH and CIH are equal since the have 2 common sides and the respective interior angles are equal. Then we have that BI=GC and also that the respective angles B and C are equal. THen also HIJ=HGJ since they fill to 180 degrees with angles that are equal.
Hence by angle-side-angle the triangles BJI and CJG are equal.
∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG
You have to find the circumference of both circles.
B= 25.12
Y= 87.92
I think this is right.
Answer:
3(k - 1)² = 12
Step-by-step explanation:
To complete the square, write the equation standard form and make the a term's coefficient 1.
3k² = 11 + 6k
3k² - 6k - 11 = 0
3(k² - 2k) = 11
Take the middle term -2k and divide the coefficient in 2 and square it. Here it is -2/2 = -1. -1² = 1. Add 1 to both sides.
3(k² - 2k + 1) = 11 + 1
3(k - 1)² = 12