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dsp73
3 years ago
10

The sum of the digits of a two digit number is 10. If 36 is subtracted from the number, the digit interchange their places Find

the number​
Mathematics
1 answer:
lianna [129]3 years ago
3 0

Step-by-step explanation:

Let A be the tens digit of the number and B be the ones digit.

We have A + B = 10 and 10A + B - 36 = 10B + A.

=> A + B = 10 and 9A - 36 = 9B

=> A + B = 10 and A - 4 = B

=> A + B = 10 and A - B = 4

Therefore 2A = 10 + 4 = 14,

A = 7 and B = 10 - 7 = 3.

Hence the number is 73.

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If Upper X overbar equals 62​, Upper S equals 8​, and n equals 36​, and assuming that the population is normally​ distributed, c
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Answer:

The 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

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Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that t_{\alpha/2}=2.72

Now we have everything in order to replace into formula (1):

62-2.72\frac{8}{\sqrt{36}}=58.373    

62+2.72\frac{8}{\sqrt{36}}=65.627    

So on this case the 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

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