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snow_lady [41]
3 years ago
11

Maya is tracking the amount of rainfall during a storm describe the domain and range for the situation include continuous or dis

crete in your description
Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

Domain = The storm (Discrete)

Range = The amount of rainfall (Discrete)

Step-by-step explanation:

A domain is the set of all the probable inputs while range is the set of probable outputs. The domain is an independent variable while the range is a dependent variable.

In this question, the amount of rainfall is dependent on whether or not there is a storm, which makes the storm an independent variable. The storm(Domain) is the input, while the amount of rainfall(Range) is the probable output.

Both the storm and the amount of rainfall are discrete because their numbers of occurrence are positive integers.

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D!

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In a certain​ chemical, the ratio of zinc to copper is 4 to 15. A jar of the chemical contains 750 of copper. How many grams of
nataly862011 [7]

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We first find amount of both zinc and copper( the whole chemical)  which is equal to

ratio of copper / total ratio  x (the entire chemical--total grams of zinc and copper) =amount of copper

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3 0
2 years ago
Look at this cylinder:
Sedbober [7]
  • Height=h=8cm
  • Radius=r=4cm

We know

\boxed{\sf \star TSA_{(Cylinder)}=2\pi r(h+r)}

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=2\times \dfrac{22}{7}\times 4(8+4)

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{176}{7}(12)

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{2112}{7}

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=301.7cm^2

Now

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  • New Height=2(8)=16cm

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=2\times \dfrac{22}{7}\times 8(16+8)

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{352}{7}(24)

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{8448}{7}

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=1204.7cm^2

So

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{1204.7}{301.7}

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{4}{1}

\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cylinder)}}:{TSA_{(Old\:Cylinder)}}=4:1}}}

Hence our correct option is Option C

6 0
2 years ago
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