We are given a diagram with different rays and lines.
Note: A line can be extend more and more upto infinitely length from both of the ends but a ray can be extend from from end only.
We need to find the rays for the line BE.
We can see BE line has a point A in between line.
So, we can name the rays formed with end point A as AB and AE.
<h3>Therefore, AB and AE rays are part of line BE.</h3><h3>So, the correct option is 2nd option :</h3><h3>AB and AE.</h3>
Given that a parking lot contains 100 cars, k of which happen to be lemons.
This is a conditional probability question.
Let event A be that a car is tested and event B be that a car is lemon.
The probability that a car is lemon is given by

The probability that a car is tested is given by

The probability that a car is lemon and it is tested is given by

For a conditional probability, the probablility of event A given event B is given by:

Therefore, the probability that a car is lemon, given that it is tested is given by.
Divide 7 by 32 and go from there
The polynomial <span>3x2y2 − 5xy2 − 3x2y2 + 2x2 can be simplified by combining like terms.
The result is:
-5xy2 + 2x2
The polynomial is
a binomial (2 terms),
the degrees is 3
the highest order in x is 2 and the highest order in y is 2.</span>