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barxatty [35]
3 years ago
14

A parking lot contains 100 cars , k of which happen to be lemons. we select m of these cars

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0
Given that a parking lot contains 100 cars, k of which happen to be lemons.

This is a conditional probability question.

Let event A be that a car is tested and event B be that a car is lemon.

The probability that a car is lemon is given by \frac{k}{100}

The probability that a car is tested is given by \frac{m}{100}

The probability that a car is lemon and it is tested is given by \frac{n}{m}

For a conditional probability, the probablility of event A given event B is given by:

P(A|B)= \frac{P(A\cap B)}{P(B)}

Therefore, the probability that a car is lemon, given that it is tested is given by.

P(lemon|tested)= \frac{P(lemon\, and\, tested)}{P(tested)}  \\  \\ = \frac{ \frac{n}{m} }{ \frac{m}{100} } = \frac{n}{m} \times \frac{100}{m} = \frac{100n}{m^2}
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Jo had $5 more than Nate and together<br> they had $43. How much did Nate have?
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Answer:

Step-by-step explanation:

43-5

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hope this helps!

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Given: ABCD is a rhombus, <br> Perimeter = 20,<br> AC:BD = 4:3 Find:<br> Area of ABCD.
REY [17]
4a=20⇒a=5

we know diagonals are perpendicular. if u look at one of the right triangles, you can see that for hypotenuse to be 5, the legs have to be 4 and 3 to satisfy the given ratio 4:3.

so, diagonals are 8 and 6 as we know that diagonals bisect each other.

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3 years ago
Triangle ABC is isosceles with AB=CB. Circle M is inscribed in Triangle ABC such that it is tangent at points D, E, and F. If th
Ierofanga [76]

Answer:

The answer is "12 inches".

Step-by-step explanation:

Please find the image file of the graph.

We know AE = CF \ and \ EB = FB so because the triangle is isosceles.

EB = 2x, FB = 2x,\ and \ CF = x when AE is called by x.

We know that AE = AD = x since E and D are tangent points to a circle.

They have CD = CF = x since D and F are tangent points only to circle.

Thus, if the perimeter is 32, the following is the result:

\to AE + EB + BF + FC + CD + DA = 32\\\\\to x + 2x + 2x + x + x + x = 32\\\\\to 8x = 32\\\\\to x = 4

Therefore the length of BC = BF + FC = 2x + x = 3x = 12\  inches

8 0
3 years ago
Jerry is planting white daisies and red tulips in his garden and he wants to choose a pattern in which the tulips surround the d
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The borders are shown in the picture attached.

As you can see, starting with border 1, we have 6 daises (white squares) surrounded by 10 tulips (colored squares). Through Jerry's expression we expected:
<span>8(b − 1) + 10 =
</span>8(1 − 1) + 10 =
0 + 10 =
10 tulips.

When considering border 2, we expect: 
<span>8(b − 1) + 10 =
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Indeed, we have the 10 tulips from border 1 and 8 additional tulips, for a total of 18 tulips.

Then, consider border 3, we expect:
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Again, this is correct: we have the 10 tulips used in border 1 plus other 16 tulips, for a total of 26.

Therefore, Jerry's expression is correct.</span>

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