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3 years ago

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Question 4 What value of p makes the equation true? p+ (40 - p) = 0

1 answer:

weeeeeb [17]3 years ago

5 0

Answer:

ye kya question kia hi koi insano wala question karo

Step-by-step explanation:

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Cho ma trận A và một sự tương ứng

algol [13]

Answer:

sorry I don't speak that language

4 0

2 years ago

During a promotional weekend, a state fair gives a free admission to every 188th person that enters the fair. On Saturday, there

damaskus [11]

Answer: 81 people

Step-by-step explanation:

Number of people that attended fair on Saturday = 6737

Number of people that got free admission = 6737/188 = 35.8.

Free admission on Saturday = 35

Number of people that attended fair on Saturday = 8669

Number of people that got free admission = 8669/188 = 46.1

Free admission on Sunday = 46

The people who received a free admission over the two days will be:

= 35 + 46

= 81 people

6 0

3 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

4 years ago

A laptop computer originally priced at $1,000 now sells for $1,300. What is the percent of increase?

Vitek1552 [10]

Answer:

30% :))))))))))))))))))))))))))))

4 0

2 years ago

Read 2 more answers

Which of the following values is greater than −3.5? −3.25 −3.75 −4.2 −5.4

fomenos

The answer is -3.25 is greater :)

6 0

1 year ago