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Ber [7]
3 years ago
9

I need help on a test asap, what is 3(x+4)

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

3x+12

Step-by-step explanation:

you multiply 4 and 3. Since this isn't a formula to find x it is added to the number outside the bracket.

Virty [35]3 years ago
8 0

Answer:

3x + 12

Step-by-step explanation:

3(x + 4)

So you multiply 3 with each of these numbers but separately. So first multiply 3 with x, since x is just by itself you pretend it´s one, and so 3 times 1 equals 3 but also add the x with it so 3x.

Then you multiply 3 times 4 which is 12.

Last, put the numbers together and create the equation:

3x + 12

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Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

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