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Alexus [3.1K]
4 years ago
5

Suppose you wanted to dissolve 109 g of sodium carbonate in enough water to make 6.00 L of solution. What is the molarity of thi

s solution?
Chemistry
1 answer:
kumpel [21]4 years ago
5 0
Molarity

a. Na2CO3
                Molar mass = 106 g/mol
    n= 109 g / (106 g/mol) = 1.028 mol

b. 6.00L

c. M=n/V
    M = 1.028 mol / 6.00 L
    M= 0.1713 mol / L

Answer: The molarity of the sodium carbonate solution is 0.1713 mol/L

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When a sample of liquid is heated, its thermal energy _______.
Ratling [72]

Answer:

Entropy.

Explanation:

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4 0
3 years ago
In a second-order reaction (one that is second order in one reactant), cutting in half the concentration of that reactant will h
svlad2 [7]
A second order reaction varies with the square of the concentration of the reactant. Therefore, halving the concentration will reduce the rate of reaction by a factor of 4.
The answer is E.
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3 years ago
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With the Haber process, how many grams of hydrogen will be needed to make 0.3820 pounds of ammonia? Needed to 3 decimal places f
masya89 [10]

30.576 g of hydrogen

Explanation:

First we need to covert the pound in grams.

if        1 pound is equal to 453.592 grams

then  0.3820 pounds is equal to X grams

X = (0.3820 ×  453.592) / 1 = 173.272 grams

So we have 173.272 grams of ammonia.

Now we look at the chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):

3 H₂ + N₂ → 2 NH₃

number of moles = mass / molar weight

number of moles of ammonia = 173.272 / 17 = 10.192 moles

Now taking in account the chemical reaction, we formulate the following reasoning:

if         3 moles of hydrogen produce 2 moles of ammonia

then    Y moles of hydrogen produce 10.192 moles of ammonia

Y = (3 × 10.192) / 2 = 15.288 moles of hydrogen

mass = number of moles × molar weight

mass of hydrogen = 15.288 × 2 = 30.576 g

Learn more about:

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4 0
4 years ago
A certain half-reaction has a standard reduction potential E0red = +0.13V . An engineer proposes using this half-reaction at the
Ivan

Answer:

a. 1.23 V

b. No maximum

Explanation:

Required:

a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?

b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

If E°cell must be at least 1.10 V (E°cell > 1.10 V),

E°red, cat - E°red, an > 1.10 V

E°red, cat - 0.13V > 1.10 V

E°red, cat > 1.23 V

The minimum standard reduction potential is 1.23 V while there is no maximum standard reduction potential.

4 0
3 years ago
State the guideline you can use to predict the formula of:
Cerrena [4.2K]

We can predict formula of ionic compounds by:

  • Take a look at where the elements are listed on the periodic table.
  • The amount of electrons that an element would need to gain or lose in order to resemble an atom of a nearby noble gas is one of the similarities that atoms in the same column as one another (group) tend to display.
  • Alkali metal group I ions have +1 charges.
  • Alkaline earth metals (group 2 ions) have a +2 charge.
  • Nonmetal group 6 ions have a charge of -2.
  • Halides in group 7 have a -1 charge.
  • The charges of the transition metals cannot be predicted in a straightforward manner.
  • Check out a table of charges (valences) to see potential values. The +1, +2, and +3 charges are most frequently employed in beginning and general chemistry courses.
  • Keep in mind that the positive ion is always stated first when writing an ionic compound's formula.

These are the few guidelines we can use to product formula.

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4 0
2 years ago
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