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gregori [183]
2 years ago
8

Give the meaning of each of the following symbols when used in a chemical equation.

Chemistry
1 answer:
nlexa [21]2 years ago
6 0

Reaction arrows are used to describe the state or progress of a reaction. 2.1 The Chemical Reaction Arrow. The chemical reaction arrow is one straight arrow pointing from reactant(s) to product(s) and by-products, sometimes along with side products. A → B. It is the most widely used arrow.

Boron is a chemical element with the symbol B and atomic number 5. Produced entirely by cosmic ray spallation and supernovae and not by stellar nucleosynthesis, it is a low-abundance element in the Solar System and in the Earth's crust

The C5 (C5) fraction is a co-product of naphtha cracking and is used as a raw material for synthetic rubber and petroleum resins.

Deuterium

Deuterium is frequently represented by the chemical symbol D. Since it is an isotope of hydrogen with mass number 2, it is also represented by 2. H. .

Unimolecular Elimination (E1) is a reaction in which the removal of an HX substituent results in the formation of a double bond. It is similar to a unimolecular nucleophilic substitution reaction (SN1) in various ways. One being the formation of a carbocation intermediate.

Aqueous (aq.): In the presence of water, often meaning water is the solvent. Aqueous NaCl. Anhydrous NaCl.

Hydrogen is the chemical element with the symbol H and atomic number 1. ... Since hydrogen readily forms covalent compounds with most nonmetallic elements, most of the hydrogen on Earth exists in molecular forms such as water or organic compounds.

Catalyst, in chemistry, any substance that increases the rate of a reaction without itself being consumed. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.

Kp is the equilibrium constant calculated from the partial pressures of a reaction equation. It is used to express the relationship between product pressures and reactant pressures. It is a unitless number, although it relates the pressures.

Hope this helps a bit?

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For the following reaction, 25.2 grams of sulfur dioxide are allowed to react with 5.36 grams of oxygen gas. sulfur dioxide (g)
Marizza181 [45]

Answer:

Maximum amount of sulfur trioxide that can be formed = 26.822 g

Explanation:

The balanced chemical equation for the reaction

2SO₂ + O₂ -----> 2SO₃

25.2 grams of sulfur dioxide are allowed to react with 5.36 grams of oxygen gas. What is the maximum amount of sulfur trioxide that can be formed?

It is the limiting reagent (the reactant in the stoichiometric lesser amount) that determines how much product is formed or how much of the other reactant is formed.

So, we convert the masses of reactants present into number of moles to get a clearer picture.

(Number of moles) = (mass)/(molar mass)

For sulfur dioxide,

Mass present = 25.2 g

Molar mass = 64.066 g/mol

(Number of moles present) = (25.2/64.066)

(Number of moles present) = 0.39 moles

For Oxygen gas,

Mass present = 5.36 g

Molar mass = 32.0 g/mol

(Number of moles present) = (5.36/32)

(Number of moles present) = 0.1675 moles

But from the stoichiometric balance,

2SO₂ + O₂ -----> 2SO₃

2 moles of Sulfur dioxide reacts with 1 mole of Oxygen gas

If Sulfur dioxide was the limiting reagent,

0.39 moles would react with (0.39×1/2) moles of Oxygen gas; 0.195 moles of Oxygen gas.

This is more than the total amount of Oxygen gas present at the start of the reaction, hence, Sulfur dioxide cannot be the limiting reagent.

Oxygen gas as limiting reagent,

1 mole of Oxygen gas reacts with 2 moles of Sulfur dioxide,

0.1675 moles of Oxygen gas would react with (0.1675×2/1) of Sulfur dioxide; 0.335 moles of Sulfur dioxide.

This indicates that oxygen is truly the limiting reagent and Sulfur dioxide is the reagent that is present in excess.

So, now, we calculate the amount of Sulfur trioxide that can be obtained from this reaction setup (assuming a 100% conversion and the maximum amount of Sulfur dioxide formed)

2SO₂ + O₂ -----> 2SO₃

1 mole of Oxygen gas gives 2 moles of Sulfur trioxide,

0.1675 moles of Oxygen gas will give (0.1675×2/1) moles of Sulfur trioxide; 0.335 moles of Sulfur trioxide.

We then convert this to mass.

(Mass) = (number of moles) × (molar mass)

Molar mass of SO₃ = 80.066 g/mol

(Mass of SO₃ produced) = 0.335 × 80.066

(Mass of SO₃ produced) = 26.822 g.

Maximum amount of sulfur trioxide that can be formed = 26.822 g

Hope this helps!!

5 0
3 years ago
Read 2 more answers
The elements in the periodic table are arranged in order of
Alenkinab [10]

Answer:

dsgadsagsdgsd

Explanation:

5 0
3 years ago
How much energy is required to vaporize 0.5kg of water?
White raven [17]

Answer:

Explanation:

Vaporization Equation => Q = m·ΔHv

m = 0.5Kg water = 500g water

ΔHv = Heat of vaporization = 540 calories/gram

∴Q = 500g x 540cal/g = 270,000 calories x 4.184 joules/cal = 1,129,680 joules = 1130 Kilojoules (3 sig. figs.)

3 0
3 years ago
PLEAEEEE HELPPP
alexgriva [62]
Speed is a scalar quantity( quantity having only magnitude). So it doesn't specifies direction. Hence option C.) 5Km/hr north is incorrect.
8 0
3 years ago
Examples of a pure substances
DiKsa [7]

Answer:

Explanation:

Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements.

3 0
2 years ago
Read 2 more answers
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