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Zigmanuir [339]
3 years ago
10

Which statement is part of the 3R rule?

Chemistry
1 answer:
makvit [3.9K]3 years ago
7 0

Answer:

The 3R rule states that Radial cracks form a Right angle on the Reverse side of the force. This rule enables an examiner to determine readily the side on which a window or pane of glass was broken.

I hope it's helpful!

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What is the total mass of kno3 that must be dissolved in 50. Grams of h2o at 60.°c to make a saturated solution?
Trava [24]

Answer:

55 g

Explanation:

First, we have to look for the solubility of KNO₃ at 60°C, considering that the solubility is the maximum amount of solute that can be dissolved in 100 grams of solvent, that is, the concentration of a saturated solution.

The solubility of KNO₃ at 60°C is 110.0 g of KNO₃ per 100 g of water. The mass of KNO₃ that must be dissolved in 50 g of water to make a saturated solution is:

50 g H₂O × (110.0 g KNO₃/100 g H₂O) = 55 g KNO₃

6 0
3 years ago
If 5.0g nitrogen dioxide completed reacted, how many grams of nitric acid would form?
lyudmila [28]

Answer:

71847284737283774737373737

6 0
2 years ago
1. Based on the data set and the true measured value being 28km.
motikmotik

Answer:

this data is both accurate and precise

4 0
3 years ago
Read 2 more answers
the radius of the Sun is approximately 696,000 kilometers, while bacterial cells are as small as 1.9 × 10-4 millimeters. Express
Mazyrski [523]

Explanation;

Writing scientific notation :

  • Move the decimal to the left side until single digit of number remains before the decimal.
  • Then we will count the number of times we moved the decimal. Write this number as the exponential power of number '10'.
  • For Example: 2894.55=2.89455\times 10^{3}

Radius of the sun = 696,000.0 kilometer

1 km=10^3 m

Radius of the sun can also be written as = 6.96\times 10^{5} km=6.96\times 10^{5}\times 10^3 m=6.96\times 10^{8} meter

Size of bacterial cell = 1.9\times 10^{-4} millimeter

1 mm=1\times 10^{-3} m

Size of bacterial cell can also be written as = 1.9\times 10^{-4}\times 10^{-3} m=1.9\times 10^{-7} meter

4 0
3 years ago
What atomic or hybrid orbital on sb makes up the sigma bond between sb and f in antimony(iii) fluoride, sbf3?
Afina-wow [57]

Answer: The four sp^3 hybridized orbitals on Sb makes up the sigma bonds between Sb and F in antimony(iii) fluoride ,SbF_3

Explanation:

According to VESPR theory:

Number of electrons around the central atom : \frac{1}{2}[V+N-C+A]

V = number of valence electrons

N = number of neighboring atoms

C = charge on cation

A = charge on an anion

In antimony(III) fluoride ,

Antimony being central atom: V= 5,N =3,C=0,A=0

Number of electrons : \frac{1}{2}[V+N-C+A]=4

Number of electrons around the central atom are 4 which means that SbF_3 molecule has four sp^3 hybridized orbitals.

6 0
3 years ago
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