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Delicious77 [7]
3 years ago
8

How many signals would you expect to find in the 1h nmr spectrum of 1 butanol?

Chemistry
1 answer:
guajiro [1.7K]3 years ago
4 0
The ¹H-NMR of 1-Butanol is shown below,

There are Five signals found in the proton NMR spectrum of 1-Butanol.

A Broad Singlet signal at ≈ 4.7 ppm (Down Field = More Deshielded) is for proton directly attached to Oxygen atom.

Triplet Signal at ≈ 3.65 ppm (Down Field = Deshielded) is for methylene group directly attached to Oxygen atom.

Multiplet Signal at ≈ 1.6 ppm is for methylene which is present between two methylene groups. The shielding effect is increasing as moving away from Oxygen atom.

Multiplet Signal at ≈ 1.4 ppm is for methylene which is present between terminal methyl and methylene groups. The shielding effect is increasing as moving away from Oxygen atom.

Triplet Signal at ≈ 0.9 ppm (Up Field = Most Shielded) is for terminal methyl group attached to methylene group.

Result:
           Five Signals are found in the ¹H-NMR of 1-Butanol.

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A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at
balandron [24]

Answer:

The final temperature of the water is 22.44°C.

Explanation:

Heat lost by tin will be equal to heat gained by the water

-q_1=q_2

Mass of tin = m_1=18.5 g

Specific heat capacity of tin = c_1=0.21 J/g^oC

Initial temperature of the tin = T_1=97.38^oC

Final temperature = T_2=T

q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.7 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=21.52^oC

Final temperature of water = T_2=T

q_2=m_2c_2\times (T-T_3)

-q_1=q_2  (Law of Conservation of energy)

-(m_1\times c_1\times (T-T_1))=m_2\times c_2\times (T-T_3)

On substituting all values:

-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)

we get, T = 22.44°C

The final temperature of the water is 22.44°C.

3 0
3 years ago
odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add
Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

Explanation :

First we have to calculate the moles of H_2SO_4.

\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}

Given:

Molar mass of H_2SO_4 = 98 g/mole

Mass of H_2SO_4 = 6.05\times 10^3kg=6.05\times 10^6g

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol

The moles of H_2SO_4 is, 6.17\times 10^4mol

Now we have to calculate the moles of Na_2CO_3

The balanced neutralization reaction is:

Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3

From the balanced chemical reaction we conclude that,

As, 1 mole of H_2SO_4 neutralizes 1 mole of Na_2CO_3

So, 6.17\times 10^4mol of H_2SO_4 neutralizes

Now we have to calculate the mass of Na_2CO_3

\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3

Molar mass of Na_2CO_3 = 106 g/mole

\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg

Thus, the mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

3 0
4 years ago
Complete the following equations (note that the equations are not balanced). Use the activity series if necessary. An activity s
umka21 [38]

The equation which we are required to complete can be completed as follows;

  • AgNO3 + KCl ==> KNO3 + AgCl

<h3>Electrochemical series;</h3>

Most substitution reactions involve displacement of metals and non-metals.

The possibility of a substitution reaction to occur is sometimes dependent on the order of preference of the metals in the activity series.

On this note, In the reaction between AgNO3 and KCl, potassium, K displaces silver, Ag and the products of the reaction are; KNO3 and AgCl

Read More on Electrochemical series;

brainly.com/question/14652325

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Organic matter plays an important part in the local, regional, and global water cycles due to its role in promoting water.
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3 years ago
Which atomic model was proposed as a result of J. J. Thomson’s work? the plum pudding model the indivisible atom model an atom t
olga2289 [7]

Answer:

A. The plum pudding model.

Hope this helps!

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4 years ago
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