1.05 Quiz: Measure Angles
2 answers:
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Answer:
9.36
Explanation:
Sodium formate is the conjugate base of formic acid.
Also,
for sodium formate is
Given that:
of formic acid =
And,
So,
Concentration = 0.35 M
HCOONa ⇒ Na⁺ + HCOO⁻
Consider the ICE take for the formate ion as:
HCOO⁻ + H₂O ⇄ HCOOH + OH⁻
At t=0 0.35 - -
At t =equilibrium (0.35-x) x x
The expression for dissociation constant of sodium formate is:
Solving for x, we get:
x = 0.44×10⁻⁵ M
pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64
pH + pOH = 14
So,
<u>pH = 14 - 4.64 = 9.36</u>
Carbon dioxide has a total of 16 valence electrons.
1. To determine the number of valence electrons of carbon dioxide (CO2), first determine the number of valence electrons of each of the elements in the molecule.
a. We have 1 carbon (C) molecule, and 2 oxygen (O) molecules.
b. The carbon molecule has 4 valence electrons and each oxygen molecule has 6 oxygen molecules.
2. Add up the valence electrons of each of the elements
4 + (2 x 6) = 16
(from C) (2 oxygen molecules, with 6 valence electrons each)
Thus, CO2 has a total of 16 valence electrons.
The number of valence electrons can be more clearly seen from the Lewis structure of the CO2 in the figure below (Source: http://chemistry.tutorvista.com/inorganic-chemistry/bonding-electrons.html). The the dots surrounding the letters represent the valence electrons.
1. To determine the number of valence electrons of carbon dioxide (CO2), first determine the number of valence electrons of each of the elements in the molecule.
a. We have 1 carbon (C) molecule, and 2 oxygen (O) molecules.
b. The carbon molecule has 4 valence electrons and each oxygen molecule has 6 oxygen molecules.
2. Add up the valence electrons of each of the elements
4 + (2 x 6) = 16
(from C) (2 oxygen molecules, with 6 valence electrons each)
Thus, CO2 has a total of 16 valence electrons.
The number of valence electrons can be more clearly seen from the Lewis structure of the CO2 in the figure below (Source: http://chemistry.tutorvista.com/inorganic-chemistry/bonding-electrons.html). The the dots surrounding the letters represent the valence electrons.
Answer:
The scaling factor is 5.
Explanation:
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In this case, since the scaling factor is defined as the ratio of the molar mass of the molecular formula (complete) to the empirical formula (simplified), it is possible to compute it for the empirical formula of CH2O whose molar mass is 30 g/mol (12+2+16) as shown below:
Therefore, we can also infer that the molecular formula would be:
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