Attached the solution and work.
5 1⁄3 − 2 3⁄4= Please help me!
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Given:
Number of students who has a cat and a dog = 5
Number of students who has a cat but do not have a dog = 11
Number of students who has a dog but do not have a cat = 3
Number of students who neither have a cat nor a dog = 2
To find:
The probability that a student has a cat given that they do not have a dog.
Solution:
Let the following events:
A = Student has a cat
B = Do not have a dog
Total number of outcomes is:
The probability that a student has a cat but do not have a dog is:
The probability that a student do not have a dog is:
The conditional probability is:
Therefore, the probability that a student has a cat given that they do not have a dog is .