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Nesterboy [21]
4 years ago
7

The following figures show four stages that occur during the formation of a one-solar-mass star. Rank these stages based on thei

r rotation rate, from fastest to slowest. (Assume that the angular momentum of the forming star is conserved throughout the formation process, though in fact it may shed some angular momentum by ejecting material into interstellar space.)
Physics
1 answer:
Stolb23 [73]4 years ago
6 0

Answer:

  • The four stages that occur during the formation of a one-solar-mass star are as follows:                                                                                

Explanation:

  1. The formation of the Red dwarf which is also one of the celestial entities inside the galaxies as, the formation of the more gradual body of the mixture of different gasses having a imaginable low temperature. As this whole process leads to the formation of the main sequence star.
  2. When the different masses of the mixtures of the gases combines to form a very celestial body then it leads to the composition of each component inside the celestial body to acquire a very flattened form of structure leading to the flattened disk with radiation properties. As the Protostar with jets is formed which means that still the star is in the process of collecting the right amount of materials for its bodily development.
  3. The star formation does take a very swift form of development when all the required number of factors are there to satisfy the formation of the star, as these star nurseries are able to collect the right level or optimum amount of energy for its formation.As, these contracting cloud trapping the infrared light or radiation inside it.
  4. Now, after the different conditions and terms for the formation of the star are satisfied then the mass or shape which the different components of the star body takes place is the molecular cloud fragment.
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The design of a 60.0 cm industrial turntable requires that it has a kinetic energy of 0.250 j when turning at 45.0 rpm. What mus
Aneli [31]

Answer:

The moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

Explanation:

Given;

radius of the turnable, r = 60 cm = 0.6 m

rotational kinetic energy, E = 0.25 J

angular speed of the turnable, ω = 45 rpm

The rotational kinetic energy is given as;

E_{rot} = \frac{1}{2} I \omega ^2

where;

I is the moment of inertia about the axis of rotation

ω is the angular speed in rad/s

\omega = 45 \frac{rev}{\min} \times \frac{2 \pi \ rad}{1 \ rev} \times \frac{1 \ \min}{60 \ s} \\\\\omega = 4.712 \ rad/s

E = \frac{1}{2} I \omega ^2\\\\I = \frac{2E}{\omega ^2} \\\\I = \frac{2 \ \times \ 0.25}{(4.712)^2} \\\\I = 0.0225 \ kg.m^2

Therefore, the moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²

5 0
3 years ago
What is your weight on Venus, assuming that the acceleration due to gravity on Venus is 8.875 m/s^2 and your mass is 50 kg.
Volgvan

Answer:

Weight on Venus = 443.75 N

Explanation:

Weight of a body is the product of mass and acceleration due to gravity.

So we have

       Weight =  Mass x Acceleration due to gravity

        W = mg

        Mass, m = 50 kg

        Acceleration due to gravity, g = 8.875 m/s²

        W = 50 x 8.875 = 443.75 N

Weight on Venus = 443.75 N

3 0
3 years ago
Read 2 more answers
A long, thin solenoid has 450 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform ra
sergey [27]

Answer:

\frac{di}{dt}  = 7.31 \  A/s

Explanation:

From the question we are told that  

     The  number of turns is  N =  450 \  turns

      The  radius is  r =  1.17 \ cm =  0.0117 \ m

       The  position from the center consider is  x =  3.45 cm  =  0.0345 m

       The  induced emf is  e  =  8.20 *10^{-6} \  V/m

Generally according to Gauss law

        \int\limits { e } \, dl  =  \mu_o *  N  *  \frac{di}{dt }  *  A

=>    e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  A

Where A is the  cross-sectional area of the solenoid which is mathematically represented as

                A =  \pi r ^2

=>      e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  \pi r^2

=>       \frac{di}{dt}  =  \frac{2e * x  }{\mu_o * N  * r^2}ggl;

Here  \mu_o is the permeability of free space with value

          \mu_o  =  4\pi * 10^{-7} \  N/A^2

=>     \frac{di}{dt}  =  \frac{2 *  8.20*10^{-6} *  0.0345  }{ 4\pi * 10^{-7} * 450  * (0.0117)^2}

=>      \frac{di}{dt}  = 7.31 \  A/s

6 0
4 years ago
Suppose there was a star with a parallax angle of 1 arcsecond. How far away would it be? Select all that apply.
lesya692 [45]

Answer:

option E

Explanation:

given,                          

Parallax angle(d) = 1 arcsecond

using Parallax formula                  

      d = \dfrac{1}{p}

 p is the parsecs angle which is measured in 1 arcsecond

 d is the distance in parsec

now,                                            

      P = \dfrac{1}{d}

      P = \dfrac{1}{1}

      P = 1 \ parsec

we know,                                  

    1 parsec = 3.26 light year

hence, the answer will be option E

6 0
4 years ago
A force acts on an object. Which option describes an action that could prevent the object from moving? (1 point)
hram777 [196]
C. because if you push a ball on one side and on the other side with the same amount of force at the same time it won’t move.
Hope this helps
8 0
3 years ago
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