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svetlana [45]
3 years ago
13

An intergalactic rock star bangs his drum every 1.50 s. A person on earth measures that the time between beats is 2.70 s. How fa

st is the rock star moving relative to the earth?
Physics
1 answer:
sineoko [7]3 years ago
7 0

Answer:

v = 83.1 % of speed of light

Explanation:

given,

T_e is the earth time = 2.7 s

T_s is the ship time = 1.5 s

we know,

T_s = T_e \times \gamma

where c is the speed of light

v is the speed of the rock star moving

T_s = T_e\times \sqrt{1-\dfrac{v^2}{c^2}}

1.5= 2.7\times \sqrt{1-\dfrac{v^2}{c^2}}

\sqrt{1-\dfrac{v^2}{c^2}} =0.556

squaring both side

1-\dfrac{v^2}{c^2}=0.3086

v^2=0.6914c^2

v = 0.831 c

v = 83.1 % of speed of light

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Answer:

No..

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Answer:

the average force 11226 N  

Explanation:

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Let's start looking for the stack speeds, it has a free fall, from rest  (Vo=0)

             

           Vf² = Vo² - 2gY

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This is the speed that the battery likes when it touches the beam.  They also give us the distance it travels before stopping, let's calculate the time

         

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             0 = Vo - g t

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             t = 12.3 / 9.8

             t = 1.26 s

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Now let's use the equation that relates the impulse to the amount of movement

                 I = Δp

                F t = pf-po

The amount of final movement is zero because the system stops

                F = - po / t

                F = - mv / t

                F = - 1150 12.3 / 1.26

                F = -11226 N

This is the average force exerted by the stack on the vean

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Answer: there are 6 atoms.

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