The magnitude of normal force that floor exerts on chair is 100.83N
<u>Explanation:</u>
Given:
Weight of chair, W = 75N
Applied force, F = 42N
Angle, θ = 38°
Normal force, n = ?
We know,
Vertical component of the force = F sinθ
= 42 X sin38°
= 42 X 0.615
= 25.83N
Total normal force acting on the chair = 75N + 25.83N
= 100.83N
Therefore, the magnitude of normal force that floor exerts on chair is 100.83N
Answer:
the tension T = 916[N]
Explanation:
We need to analyze the sketch that is in the attached image, here we can find the free body diagram with the forces acting over him.
The weight is equal to the product of the mass by the gravity
w = m*g = 78.9[kg] * 9.81[m/s^2]
The acceleration given by the helicopter is 1.8 [m/s^2]
The sum of forces on the body must be equal to mass by acceleration.
The only forces acting are the tension of the cable and the weight of man, these forces are equal to the product of mass by acceleration.
Answer: 0.516 ft/s
Explanation:
Given
Length of ladder L=20 ft
The speed at which the ladder moving away is v=2 ft/s
after 1 sec, the ladder is 5 ft away from the wall
So, the other end of the ladder is at
Also, at any instant t
differentiate w.r.t.
Chemicals are released by the damaged tissue to bring platelets to the area to become sticky and to plug the vessels. An inflammatory response occurs which brings immune cells to fight infection and other clotting factors come to begin forming a new tissue.
Answer:
Horizontal integration is the process of a company increasing production of goods or services at the same part of the supply chain
Explanation: