Answer:
0.12 x 15 = 1.8
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given: △ABC, BC>AC, D∈ AC , CD=CB
To prove: m∠ABD is acute
Proof: In ΔABC, the angle opposite to side BC is ∠BAC and the angle opposite to side AC is ∠ABC.
Now, it is given that BC>AC, then ∠BAC>∠ABC.. (1)
In ΔBDC, using the exterior angle property,
∠ADB=∠DBC+∠BCD
∠ADB=∠DBC+∠BCA
⇒∠ADB>∠BAC (2)
From equation (1) and (2), we get
∠ADB>∠BAC
⇒∠ADB>∠ABC
⇒DB>AB
Hence, m∠ABD is acute
Answer:C
Step-by-step explanation:
A.B.C+A.B'.C+A'.B.C+A.B.C'
By distributive law : A.B.C+A.B.C' = A.B(C+C')
By complement law: C+C'=1, so
A.B(C+C')=A.B
Therefore the answer will be A.B'.C+A'.B.C+A.B