Answer:
Ques 1 - 
Ques 2 - 
Step-by-step explanation:
Ques 1: From the table, we see the relation,
5 = 2 × 2 + 1
9 = 2 × 4 + 1
13 = 2 × 6 + 1
17 = 2 × 8 + 1
21 = 2 × 10 + 1
That is, the relation from the table is given by, , where x is the input and y is the output.
Hence, the required equation is .
Ques 2: From the table, we see that,
2 = 12 × 0 + 2
14 = 12 × 1 + 2
26 = 12 × 2 + 2
38 = 12 × 3 + 2
50= 12 × 4 + 2
That is, the relation from the table is given by, , where x is the input and y is the output.
Hence, the required equation is .
Fraction: 1/20
Decimal: 0.05
Answer:
x = 5
Step-by-step explanation:
To break this down, I'll start from the first thing the question gives you. Triangle ACB is congruent to triangle DCE. This means that the angles and the sides of each triangle is the same. Now this next part is important. The way in which the letters are ordered is corresponds to what angles are the same. Since the triangles are congruent, ∠A in ΔACB would correspond to ∠D in DCE. Another example: ∠C in ACB is congruent to ∠C in ΔDCE. So if ∠A is congruent, or the same as ∠D, this means ∠D is 50°. Now, we just solve for x:
∠D = 10x
50° = 10x
Divide each side by 10 to isolate x:
50/10 = 10x/10
x = 5
Given:
ratio of stickers to erasers: 3 to 8
She has 12 stickers.
3:8 = 12:x
3x = 8*12
3x = 96
x = 96/3
x = 32 erasers.
Mrs. Robbins has 32 erasers.
