100 = 10^2
so 10^9 * 10^2 = 10^11 kilometers in 100 years
1. F(3)= -2(3)-5
-6-5
F(3)=-11
2. F(3)= -2(3)^2-4
-6^2-4
36-4
F(3)=32
3. F(x)=−2x−5
For: x=−2, f(x) is:f(−2)=(−2×−2)−5=4−5=−1
For: x=−1, f(x) is:f(−1)=(−2×−1)−5=2−5=−3
For: x=1, f(x) is:f(1)=(−2×1)−5=−2−5=−7
For: x=2, f(x) is:f(2)=(−2×2)−5=−4−5=−9
The Range is:
{−1,−3,−7,−9}
4. -80, -110
Answer:
it will take 7 nights
Step-by-step explanation:
The numbers are (-8, 3) or (3, -8).
Step-by-step explanation:
- Step 1: Given the product of the numbers are -24 and their sum are -5. Let the numbers be a and b. Form equations out of these details.
⇒ a + b = -5 ⇒ b = -5 - a
⇒ a × b = -24 -------- (1)
- Step 2: Substitute the value of b in eq(1)
⇒ a × (-5 - a) = - 24
⇒ -5a - a² = -24
⇒ a² + 5a - 24 = 0
- Step 3: Solve the quadratic equation for a.
a = (-5 ± √25 - 4 × 1 × -24)/2
= (-5 ± √121)/2
= - 16/2, 6/2 = -8 or 3
- Step 4: For each value of a, find b.
When a = -8, b = -5 +8 = 3
When a = 3, b = -5 - 3 = -8.
9514 1404 393
Answer:
- Tyler
- 2 hundredths of a mile
Step-by-step explanation:
The graph is a little difficult to read, but we note that there are 6 grid lines between times that are 2 minutes apart. So, each grid line stands for 2/6 = 1/3 minute.
At the 1-mile mark, the graph crosses 1 grid line above 8 minutes, indicating it takes Tyler 8 1/3 minutes to run 1 mile.
Then in 10 minutes, Tyler will run ...
distance = speed · time = 1 mile/(8 1/3 min) · 10 min
= 1/(25/3)·10 = 10·3/25 = 30/25 = 1.2 . . . . miles
__
The equation tells you that Elena runs each mile in 8.5 minutes. To see how far she runs in 10 minutes, we can solve ...
10 = 8.5x
x = 10/8.5 ≈ 1.18 . . . . miles
So, Tyler runs farther in 10 minutes by a distance of ...
1.20 -1.18 = 0.02 . . . . miles
