9514 1404 393
Answer:
Rajan gets 6 marks more
Step-by-step explanation:
Neerav's marks are (15)(4) +(5)(-2) = 60 -10 = 50.
Rajan's marks are (14)(4) = 56.
Rajan gets 6 more marks than Neerav.
The answer to question 3 is D. 15(4a+3). And the answer to question 4 is A. 90. Have a great day
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
gaira ALSO multiplied 6 by x, when 6 doesnt have 6x.
so the correct answer would be only -3.8(-7.5) + 6 which is 34.5.
X^2-21 divided by x-7 equals x+3
