The probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
<h3>How to determine the probability?</h3>
The distribution of the puppies is given as:
4 poodles, 5 terriers, and 2 retrievers
The probability of selecting a terrier is;
P(terrier) = 5/11
The probability of selecting a retriever is;
P(retriever) = 2/11
The required probability is
P = 5/11 * 2/11
Evaluate
P = 10/121
Hence, the probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
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Answer:
66 ≤ f ≤100
Explanation
Mean= ( Σ x ) / n
Mean= sum of scores/ number of subject she took
Now, she already too 3 subject which sum is 85+83+86=254
Now we need to know range of score for her to have (grade) a mark between 80 and 89
Now let take the lower limit mean=80
The lowest score she can get is
Mean = ( Σx) / n
80=(85+83+86+f)/4
80×4= 254+f
Therefore, f= 320-254=66
Therefore the minimum score she can have to have a B is 66.
Then, let take the upper limit mean 89. i.e the maximum she can have so that she don't have an A grade.
Mean = ( Σx) / n
89=( 83+85+86+f)/4
89×4= 254+f
f= 356-254
f=102.
Therefore this shows that she cannot have an A grade in the exam. The maximum score for the exam is 100.
There the range of score is 66 ≤ f ≤100 to have a B grade
66 ≤ f ≤100 answer
Since she cannot score 102 in the examination.
Answer:
A or d to narrow it down
Step-by-step explanation:
Hopefully you can figure out which one I am sorry.
