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marishachu [46]

3 years ago

8

Help!!! Please I don’t know how to do it !!

2 answers:

Taya2010 [7]3 years ago

7 0

U put two dots on the line to make one

sveticcg [70]3 years ago

7 0

Graph you y intercept which is 5. and then do rise over run. from your y intercept you move up three points and to the right four. then thats where you plot your first point. to plot your second point you would do the same thing to get your first point but instead of from your y intercept you would do it from your new point.

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Factor 5(2x+7)+4(2x+7)<br>enter your answer in the box

AfilCa [17]

Answer:

18x+63

Step-by-step explanation:

First you've to simplfy it, multiply the first bracket by 5 and the second by 4.

= (5)(2x)+(5)(7) + (4)(2x)+(4)(7)

= 10x+35+8x+28

Combine Like Terms:

= 10x+35+8x+28

= (10x+8x)+(35+28)

= 18x+63

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3 years ago

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If ON is a midsegment of KLM, find LM.<br><br> A.2<br> B.3<br> C.4<br> D.5

Aleksandr-060686 [28]

NO is 2 times LM

2(x+1) = 4x

2x + 2 = 4x

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1 = x

Plug that in for 4x

4(1)

4

4 0

3 years ago

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Alexandra and Mason are employees for a company. Alexandra is making a salary of $49,329. Alexandra is earning a salary that is

NeX [460]

Answer:

$67,580.73

Step-by-step explanation:

$49,329÷100=$493.29 (1%)

$493.29×37=$18,251.73 (37%)

$49,329+$18,251.73=$67,580.73

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3 years ago

Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil

andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that $p = 0.26$

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that $n = 5$

4 failures, so 1 success, and we have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898$

0.3898 = 38.98% probability that there will be 4 failures

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3 years ago

What are the solutions to the quadratic equation x^2+6x=40

kodGreya [7K]

<span>x = 10 or x = -4. It's one of those 2, there's 2 solutions for what I solved.</span>

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