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nata0808 [166]
3 years ago
14

Gymnastic lessons cost $30 per week. How much will 18 weeks of gymnastic lessons cost

Mathematics
2 answers:
Vladimir [108]3 years ago
7 0
Just do 30 multiply 18
WINSTONCH [101]3 years ago
5 0
It will cost $540
$30 times 18 =540
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Please help thank you!
Akimi4 [234]
C. is the answer

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3 0
3 years ago
In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
X - 4y = 15<br> a =<br> b=<br> C=
Free_Kalibri [48]

Answer:

use something called tiger algerbra

Step-by-step explanation:

3 0
3 years ago
Need help on 1 and 2 plzzz help !!!!!
Vesna [10]
Subtract 1 to 13. so you got 12. divide 4 so you can get the S by it self.S=3.
6 0
3 years ago
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A coin is tossed 1000 times. If the probability of getting a head is 0.545, what is the probability of getting a tail?
prohojiy [21]

Answer:

0.454 duhhhhhhhhhhh

Step-by-step explanation:

4 0
3 years ago
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