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3 years ago

Will give brainliest Question on the picture

Mathematics

1 answer:

raketka [301]3 years ago

3 0

Answer:

Step-by-step explanation:

since i helped can i have brainlist please :D

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Consider the following equation:

Sidana [21]

So you would plug in 0 for a from the beginning since this is numerical slope definition of a derivative

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3 years ago

How to find area of a rectangle?

anyanavicka [17]

Formula

Area = L*w

Hint : To find the area of a rectangle , multiply the length times the width

I hope that's help !

4 0

3 years ago

The water level in a lake decreased by 2 1/4 inches in march and increased by 1 5/8 inches in april. Determine wether the water

mezya [45]

Change in level is given by :

C = increase in level - decrease in level.

Now,

Decrease in level in March is 2 1/4 = 9/4 inches.

Increase in level in April is 1 5/8 = 13/8 inches.

Putting value of these in above equation, we get :

C = 13/8 - 9/4

C = 13/8 - 18/8

C = -5/8 inches

Therefore, the overall level after April will decrease by 5/8 inches.

Hence, option 4. is correct.

3 0

3 years ago

Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me

o-na [289]

Answer:

$\frac{3}{2}$

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

= - cos60cosx - sin60sinx

= - $\frac{1}{2}$ cosx - $\frac{\sqrt{3} }{2}$ sinx

squaring to obtain cos² (120 + x)

= $\frac{1}{4}$ cos²x + $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

= -cos60cosx + sin60sinx

= - $\frac{1}{2}$ cosx + $\frac{\sqrt{3} }{2}$ sinx

squaring to obtain cos²(120 - x)

= $\frac{1}{4}$ cos²x - $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + $\frac{1}{4}$ cos²x + $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x + $\frac{1}{4}$ cos²x - $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

= cos²x + $\frac{1}{2}$ cos²x + $\frac{3}{2}$ sin²x

= $\frac{3}{2}$ cos²x + $\frac{3}{2}$ sin²x

= $\frac{3}{2}$ (cos²x + sin²x) = $\frac{3}{2}$

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3 years ago

So How's Everyone's Day Going?

Alex777 [14]

Answer:

meh

Step-by-step explanation: complicated

8 0

3 years ago