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Eva8 [605]
3 years ago
6

Will give brainliest Question on the picture

Mathematics
1 answer:
raketka [301]3 years ago
3 0

Answer:

12

Step-by-step explanation:

since i helped can i have brainlist please :D

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Consider the following equation:
Sidana [21]
So you would plug in 0 for a from the beginning since this is numerical slope definition of a derivative

3 0
3 years ago
How to find area of a rectangle?
anyanavicka [17]

Formula

Area = L*w


Hint : To find the area of a rectangle , multiply the length times the width


I hope that's help !


4 0
3 years ago
The water level in a lake decreased by 2 1/4 inches in march and increased by 1 5/8 inches in april. Determine wether the water
mezya [45]

Change in level is given by :

C = increase in level - decrease in level.

Now,

Decrease in level in March is 2 1/4 = 9/4 inches.

Increase in level in April is 1 5/8 = 13/8 inches.

Putting value of these in above equation, we get :

C = 13/8 - 9/4

C = 13/8 - 18/8

C = -5/8 inches

Therefore, the overall level after April will decrease by 5/8 inches.

Hence, option 4. is correct.

3 0
3 years ago
Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
o-na [289]

Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x + \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

5 0
3 years ago
So How's Everyone's Day Going?
Alex777 [14]

Answer:

meh

Step-by-step explanation: complicated

8 0
3 years ago
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