The answer's 2.2
I'm sorry I can't show you, but LaTex doesn't allow you to show short division.
You can find out how to do it here, on Wikipedia's page. https://www.wikiwand.com/en/Short_division
Answer:
2a(b^3 - 7b + 8)
Step-by-step explanation:
I'm assuming that 2a2b3 is 2a2b^2. If not, this answer isn't correct.
Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.
2a2b3 - 14ab + 16a
2(ab^3 - 7ab +8a)
2a(b^3 - 7b + 8)
Answer:
No it is not a solution
Step-by-step explanation:
To solve this, you should replace your (x,y) with (8,3)- 8 being your x value and 3 being your y value.
So this inequality, your y value is supposed to be bigger than the value of whatever 3x-4 equals.
So, your inequality should be 3>3(8)-4
3*8=24-4=20
So is 3>(greater than)20? No. Which then means that (8,3) is not a solution because it would make the inequality not true.
Hope this helps!
X^2 - y^2 - 2x + 6y - 8
<span>= (x^2 - 2x + 1) - (y^2 - 6y + 9) - 8 - 1 + 9 </span>
<span>= (x - 1)^2 - (y - 3)^2 </span>
<span>= [(x - 1) - (y - 3) ] [(x - 1) + (y - 3)] </span>
<span>= (x - 1 - y + 3) ( x - 1 + y - 3) </span>
<span>= (x - y + 2) (x + y - 4)</span>
Answer:
C
Step-by-step explanation:
You just need to convert some of the mixed numbers so that they have a denominator (of the fraction part) as 8:
10 4/8 = 10 1/2
10 6/8 = 10 3/4
11 2/8 = 11 1/4
