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JulijaS [17]
2 years ago
5

The equation d = d equals StartFraction m Over V EndFraction. can be used to calculate the density, d, of an object with mass, m

, and volume, V. Which is an equivalent equation solved for V?
Mathematics
2 answers:
Alisiya [41]2 years ago
6 0

Answer:

m/d = V

Step-by-step explanation:

Bad White [126]2 years ago
5 0

Answer:

m/d=V

Step-by-step explanation:

I did the quiz

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I need this assignment done will give brainliest and extra points.
Travka [436]

Answer:

1a.2.5x³-2.25x²+3.5x-1.5

1b.No, they aren't equal. (worked out the product for both and they weren't equal, see below)

2a.-2x⁶+7x⁴+3x³-3x²+11x+20

2b.Yes. When multiplying, it doesn't matter which term/expression you put first

3. The equation has two solutions: x=-2, x=3

Step-by-step explanation:

1. (a)

(0.5x-0.25)(5x²-2x+6)

0.5x(5x²-2x+6)-0.25(5x²-2x+6)

2.5x³-x²+3x -1.25x²+0.5x-1.5

2.5x³-2.25x²+3.5x-1.5

(b)

(0.25x-0.5)(5x²-2x+6)

0.25x(5x²-2x+6)-0.5(5x²-2x+6)

1.25x³-0.5x²+1.5x -2.5x²+x-3

1.25x³-3x²+2.5x-3

This is not equal to our answer for 1(a), so we can see they're not the same.

2(a)

(-2x³+x-5)(x³-3x-4)

-2x³(x³-3x-4) +x(x³-3x-4) -5(x³-3x-4)

-2x⁶+6x⁴+8x³ +x⁴-3x²-4x -5x³+15x+20

-2x⁶+7x⁴+3x³-3x²+11x+20

(b)

Yes. When multiplying, it doesn't matter which term/expression you put first: xy=yx. For example, 2(3)=6 and 3(2)=6.

3

2x²-2x-12=0

(divide each term by 2)

x²-x-6=0

(x+2)(x-3)=0

Anything multiplies by zero is zero, so either x+2=0 or x-3=0

If x+2=0, x=-2. If x-3=0, x=3.

The equation has two solutions: x=-2, x=3

8 0
2 years ago
Suppose y varies directly as x, and y = 21 when x = 3. Find x when y = 42.
nata0808 [166]

Answer:

x = 24

Step-by-step explanation:

y₂ - y₁

42 - 21 = 21

x + 21

3 + 21 = 24

So when y increases by 21, so does x.

x = 24

7 0
3 years ago
Check that 2b+b and 3b have the same value when b is 1,2, and 3. Do 2b+b and 3b have the same value for all values of b? Explain
Inessa [10]

Answer:

Expression 2b+b and 3b have same values for all values of b.

Step-by-step explanation:

Given the two expression 2b+b and 3b and values of b as 1, 2 and 3.

Consider first expression that is, 2b+b.

Substituting the value of b=1,

2\left(1\right)+\left(1\right)=2+1=3 ....1

Substituting the value of b=2,

2\left(2\right)+\left(2\right)=4+2=6 ....2

Substituting the value of b=3,

2\left(3\right)+\left(3\right)=6+3=9 ....3

Consider second expression that is, 3b.

Substituting the value of b=1,

3\left(1\right)=3 ....4

Substituting the value of b=2,

3\left(2\right)=6 ....5

Substituting the value of b=3,

3\left(3\right)=9 ....6

For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.

Therefore both expression are same for all values of b.

3 0
2 years ago
Graph the image of this figure after a dilation with a scale factor of 2 centered at the origin.
zavuch27 [327]
Find ever origin and then   multiplying by the  <span>scale factor of 2 and i promise you will get your answer</span>
3 0
3 years ago
He found a quotient of 7 which division problem was he using?
marshall27 [118]
The answer is 3 1/2 divided by 1 1/2 because those equal 7.
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6 0
2 years ago
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