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crimeas [40]
3 years ago
9

Cuanto vale d+2c-(3a-2b) si a=2,b=-3,c=1,d=-2

Mathematics
1 answer:
kherson [118]3 years ago
3 0
<h3>Solution:</h3>

given \:  \: a=2,b=-3,c=1,d=-2 \\ then \:  \: d + 2c - (3a - 2b) \\  = ( - 2) + 2(1) - (3 \times 2 - 2 \times  -3) \\  =  - 2 + 2 - (6 + 6) \\  = 0 - 12 \\  =  - 12

<h3>Answer:</h3>

-12

<h3>Hope it helps..</h3>

ray4918 here to help..

Gracias!!

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