Question

Cuanto vale d+2c-(3a-2b) si a=2,b=-3,c=1,d=-2

Answer 1

Solution:

$given \: \: a=2,b=-3,c=1,d=-2 \\ then \: \: d + 2c - (3a - 2b) \\ = ( - 2) + 2(1) - (3 \times 2 - 2 \times -3) \\ = - 2 + 2 - (6 + 6) \\ = 0 - 12 \\ = - 12$

Answer:

-12

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