Answer:
b and c
Step-by-step explanation:
quadratic equations produce u-shaped or upside-down u-shaped graphs
If you were to graph each of the equations you would see only 'b' and 'c' do that; also, they are the only equations where the x is squared (but not in the denominator) and y is not raised to a power
The values of y are 7, 8.5, 10.5 and 11
<h3>How to determine the values of y?</h3>
The equation is given as:
y = 1/2x + 5
The domain is given as:
Domain = 4, 7, 11, 12
This means that
x = 4, 7, 11, 12
Substitute x = 4, 7, 11, 12 in the equation y = 1/2x + 5
So, we have:
y = 1/2 * 4 + 5 = 7
y = 1/2 * 7 + 5 = 8.5
y = 1/2 * 11 + 5 = 10.5
y = 1/2 * 12 + 5 = 11
Hence, the values of y are 7, 8.5, 10.5 and 11
Read more about linear function at:
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Answer:
A ) subtract the second equation from the first equation
Step-by-step explanation:
2x + 3y = 7
2x - 4y = -5
subtracting the second equation from the first equation we get,
7y = 12
y=12/7
This is the correct option
5 3/5, 27/5, 33/6 , hope I helped lmk if I got it right
If x² = 196, then we must do the inverse (square root) to find x. However, the square root of any positive number will always be ± (plus or minus).
That means you have to do:
√196 = x
x = <span>±14.
We can check this by doing:
14 </span>× 14 = 196
-14 × -14 = 196
Therefore the answer is B) -14, 14.
