Answer:
P(B) = 0.65
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
![P(B|A) = \frac{P(A \cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D)
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
![P(A) = 0.26, P(B|A) = 0.65](https://tex.z-dn.net/?f=P%28A%29%20%3D%200.26%2C%20P%28B%7CA%29%20%3D%200.65)
They are independent events, which means that
. So
![P(B|A) = \frac{P(A \cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D)
![0.65 = \frac{P(A)*P(B)}{P(A)}](https://tex.z-dn.net/?f=0.65%20%3D%20%5Cfrac%7BP%28A%29%2AP%28B%29%7D%7BP%28A%29%7D)
![P(B) = \frac{0.65P(A)}{P(A)}](https://tex.z-dn.net/?f=P%28B%29%20%3D%20%5Cfrac%7B0.65P%28A%29%7D%7BP%28A%29%7D)
![P(B) = 0.65](https://tex.z-dn.net/?f=P%28B%29%20%3D%200.65)
Answer:
Step-by-step explanation:
y = arctan(x+pi/2) use that tan y = x is y= arctan x
tan y = x+pi/2; change x with y and find y
tan x= y +pi/2; subtract pi/2 from both sides
-pi/2 + tan x = y
y= tan x -(pi/2) is the inverse function
you can also write it as
y = 1/2(2 tan x -pi)
X=side length of a campsite
12x(5+x)=1248 because each campsite has a length of x and there are 12 and from the top of the camp to the water is the 5 yds + a side length and LW=1248
60x+12x^2=1248
12x^2+60x-1248=0
x^2+5-14=0
(x+7)(x-2)=0
x+7=0 or x-2=0
x=-7 or x=2
x=2 because width can't be negative
the width of one campsite is 2 yds
4 is the length and the perimeter is 22<span />