Answer:
Step-by-step explanation:
The given equality hold true when x = 2.
Put x = 2 in inequality.
2(2) + 3 = 4+3 = 7 = R.H.S.
For x = 4 and 6, L.H.S(2x+3) is greater than 7.
Hence for x = 2, 4 and 6, the above inequality holds true.
Hope this helps!
Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
Vertical : Angles 1 & 4 Supplementary: 5 & 6
Step-by-step explanation:
Vertical angels are angles that have the same measure that are opposites of each other (1 & 4) and supplementary angles are 2 angles that equal 180 degrees that are right next to each other or right above each other (5 & 6) (3 & 5)
Answer:
Option (B)
Step-by-step explanation:
From the figure attached,
ΔBCD and ΔACE are the similar triangles.
Therefore, by the property of similar triangles, corresponding sides of these similar triangles will be proportional.
AB + 6 = 24
AB = 18
Option (B) will be the answer.
