Note that <span>x^2+y^2=16x−26y−133 represents a circle.
x^2 - 16x + y^2 + 26y = 133
x^2 - 16x + 64 - 64 + y^2 + 26y + 169 - 169 = 133 (completing the square)
Then (x-8)^2 - 64 + (y+13)^2 - 169 = 133
Simplifying, (x-8)^2 + (y+13)^2 = 133 + 169 + 64 = 366
This circle acts as a constraint on the value of 6x-8y. Assume that x and y are both on the circle. Just supposing that x = 10, find y:
(10-8)^2 + (y+13)^2 = 366, or 4 + (y+13)^2 = 366, or (y+13)^2 = 362
This is a quadratic equation that could be solved for y, and the result(s) could be subst. into the expression 6x-8y.
If you were to repeat this exercise several times, for different values of x, you'd come up with various values of 6x-8y and in that way approach (if not find) a definite answer to "</span><span>Given that x2+y2=16x−26y−133, what is the biggest value that 6x−8y can have?"
Hope someone else can come up with a more elegant approach.</span>
Answer:
Step-by-step explanation:
PEMDAS is a set of rules which are followed while solving mathematical expressions. These rules start with Parentheses, and then operations are performed on the exponents or powers. Next, we perform operations on multiplication or division from left to right. Finally, operations on addition or subtraction are performed from left to right.
Answer:
C
Step-by-step explanation:
180 degrees + 30 =210 degrees
210 degrees equals 7π/6
Answer:
y = x^2 + 8x - 3
y = x^2 + 8x + (8/2)^2 - 3 - (8/2)^2
y = x^2 + 8x + 16 - 3 - 16
Step-by-step explanation:
