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3 years ago

Solve for y when x =0 -9x-2y=-20

2 answers:

6 0

-9x - 2y = -20, x = 0

Plug in 0 for x.

-9(0) - 2y = -20

Simplify.

0 - 2y = -20

-2y = -20

Divide both sides by -2.

y = -20/-2

Simplify.

y = 10

~Hope I helped!~

madam [21]3 years ago

5 0

substitute 0 for x in the equation.

-9(0) - 2y= -20

0 - 2y = -20

-2y= -20 (divide by -2)

y = 10

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Simplify this rational expression. 2x^2+5x+3/2x^2-x-3

Murljashka [212]

Answer:

$2x+3$ / $2x-3$

Step-by-step explanation:

firstly we make two steps to simplify this question.

1st step: simplify $2x^{2} +5x+3$

to simplify this we use factorization

$2x^{2} +2x+3x+3$

$2x(x+1) +3(x+1)$

$(2x+3) (x+1)$ .....(1)

2nd step:simplify $2x^{2} -x-3$

$2x^{2} +2x-3x-3$

$2x(x+1)-3(x+1)$

$(2x-3)(x+1)$ .....(2)

now dividing (1) and (2), we get the answer

$2x+3/2x-3$

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2 years ago

25% of all who enters a race do not complete. 30 haveentered.

nikklg [1K]

Answer:

The probability that exactly 5 are unable to complete the race is 0.1047

Step-by-step explanation:

We are given that 25% of all who enters a race do not complete.

30 have entered.

what is the probability that exactly 5 are unable to complete the race?

So, We will use binomial

Formula : $P(X=r) =^nC_r p^r q^{n-r}$

p is the probability of success i.e. 25% = 0.25

q is the probability of failure = 1- p = 1-0.25 = 0.75

We are supposed to find the probability that exactly 5 are unable to complete the race

n = 30

r = 5

$P(X=5) =^{30}C_5 (0.25)^5 (0.75)^{30-5}$

$P(X=5) =\frac{30!}{5!(30-5)!} \times(0.25)^5 (0.75)^{30-5}$

$P(X=5) =0.1047$

Hence the probability that exactly 5 are unable to complete the race is 0.1047

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3 years ago

Which is greater 78.61 or78.6

ANTONII [103]

Answer:

78.61 is greater than 78.6.

Step-by-step explanation:

Adding a zero to 78.6, resulting in 78.60, makes it easier to compare 78.6 and 78.61. 78.61 is greater than 78.6.

7 0

3 years ago

The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$