Answer:
<em>The coordinates of the vertex are (-1,-4).</em>
Step-by-step explanation:
<u>Equation of the Quadratic Function
</u>
The vertex form of the quadratic function has the following equation:
Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.
We are given the function:
We must transform the equation above by completing squares:
The first two terms can be completed to be the square of a binomial. Recall the identity:
Thus if we add and subtract 1:
Operating:
The trinomial in parentheses is a perfect square:
Adding 4:
Comparing with the vertex form of the quadratic function, we have the vertex (-1,-4).
The coordinates of the vertex are (-1,-4).
Answer:
C. 2
Step-by-step explanation:
Look at pic below.
Hope this helps! :)
Adjusted balance = 622.82 - 45.45 + 78.91 + 16.36 = 672.64
Adjused balance method finance charges = 672.64 x 0.1195/12 = 6.70
Average daily balance = ((622.82 x 3) + (577.37 x 6) + (656.28 x 15) + 672.64 x 6)) / 30 = (1868.46 + 3464.22 + 9844.20 + 4035.84) / 30 = 640.42
Daily balance method finance charges = 640.42 x 0.1195/12 = 6.38
Your answer would be ten times the ingredients it would take to make ONE pancake.
What kind of question is this?
Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.
Step-by-step explanation:
Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.
Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.
Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB
⇒ 6/x = 12/6
⇒ 6/x = 2
⇒ x = 3 inches
Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.
⇒ 
⇒
⇒
⇒
⇒
⇒AD = 5 inches
