4 1/3, 4 1/2, 4 5/6, 5 1/6, 5 2/3, 5 6/6
All it takes for a relation to be a function is for each possible first number of a pair there's only one possible second number.
So if any of the sets has two pairs with the same first number, that one's not a function.
The last one has (3,2) and (3,5) so isn't a function.
I have to see if you can get it done before the first day of the shower