<span> i'm going to be slightly extra careful in showing each step. specific, ln [n / (n+a million) ]= ln n - ln(n+a million). So, we've sum(n=a million to infinity) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) [ln n - ln(n+a million)] = lim(ok--> infinity) (ln a million - ln 2) + (ln 2 - ln 3) + ... + (ln ok - ln(ok+a million)) = lim(ok--> infinity) (ln a million - ln(ok+a million)), for the reason that fairly much all the words cancel one yet another. Now, ln a million = 0 and lim(ok--> infinity) ln(ok+a million) is countless. So, the sum diverges to -infinity. IM NOT COMPLETELY SURE
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Answer:
I think it would be finding the quantity in each group.
Step-by-step explanation:
Because there would be more than 1 group. there is only one group. so you are trying to find the number of hours each person in the group will get.
i think that is right sorry if not.
Answer: 20 minutes
Step-by-step explanation:
An hour is 60 minutes, so (1/3)(60 min) = 20 min.
25 + 35 = 60
300/60 = 5
the answer is 5 packets
