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Degger [83]
4 years ago
9

Choose the expression that is equivalent to the expression 3(2x-1)

Mathematics
1 answer:
nasty-shy [4]4 years ago
5 0
THE SIMPLIFIED ANSWER IS: 6x−3<span>
</span>

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Gina puts $ 4500 into an account earning 7.5% interest compounded continuously. How long will it take for the amount in the acco
Elza [17]

~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$5150\\ P=\textit{original amount deposited}\dotfill & \$4500\\ r=rate\to 7.5\%\to \frac{7.5}{100}\dotfill &0.075\\ t=years \end{cases}

5150=4500e^{0.075\cdot t} \implies \cfrac{5150}{4500}=e^{0.075t}\implies \cfrac{103}{90}=e^{0.075t} \\\\\\ \log_e\left( \cfrac{103}{90} \right)=\log_e(e^{0.075t})\implies \log_e\left( \cfrac{103}{90} \right)=0.075t \\\\\\ \ln\left( \cfrac{103}{90} \right)=0.075t\implies \cfrac{\ln\left( \frac{103}{90} \right)}{0.075}=t\implies\stackrel{\textit{about 1 year and 291 days}}{ 1.8\approx t}

4 0
2 years ago
Do you think a polynomial can be a factor of another polynomial?
Vladimir [108]

Answer:

Yes

Step-by-step explanation:

Example

x+2 is a factor of 2x+4.

2(x+2) = 2x+4.

6 0
3 years ago
Name two planes that intersect in SW in the figure to the right
Brums [2.3K]

Answer:

a is the right answer you got this

Step-by-step explanation:

4 0
3 years ago
What is the greatest common factor of 40 and 36
Kazeer [188]

Nobody goes around with lists of greatest common factors in their head. 
When we need to know one, we grab the nearest pencil and work it out.

The factors of  40  are  1,  2,  4,  5,  8,  10,  20, and  40 .

The factors of  36  are  1,  2,  3,  4,  6,  9,  12,  18, and  36 .

The common factors of  35  and  40  are  1,  2, and  4 .

The biggest one is  4 .

7 0
4 years ago
Read 2 more answers
!!Plz urgent help!!
Firdavs [7]

Answer:

890 beads can be fitted in the triangular prism.

Step-by-step explanation:

If we can fill the spherical beads completely in the triangular prism,

Volume of the triangular prism = Volume of the spherical beads

Volume of triangular prism = Area of the triangular base × Height

From the picture attached,

Area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height})

                                             = \frac{1}{2}(AB)(BC)

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

(13)² = 5² + BC²

169 = 25 + BC²

BC² = 144

BC = 12

Area of the triangular base = \frac{1}{2}(5)(12)

                                             = 30 cm²

Height of the triangular prism = 18 cm

Volume of the triangular prism = 30 × 18

                                                   = 540 cm³

Volume of one spherical bead = \frac{4}{3}\pi r^{3}

                                                   = \frac{4}{3}\pi (0.525)^{3}

                                                   = 0.606 cm³

Let there are 'n' beads in the triangular prism,

Volume of 'n' beads = Volume of the prism

540 = 0.606n

n = 890.90

n ≈ 890

Therefore, 890 beads can be fitted in the triangular prism.

3 0
3 years ago
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