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GenaCL600 [577]
3 years ago
10

What is the total surface area of the square pyramid? ​

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

D

Step-by-step explanation:

A_1 = a^2 = 14^2 = 196

A_2 = 4(\frac{b * h}{2}) = 4(\frac{14 * 12}{2}) = 4(\frac{168}{2}) = 4 * 84 = 336

SA = A_1 + A_2 = 196 + 336 = 532\ cm^2

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Select the correct answer.
r-ruslan [8.4K]

Answer:

E

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the area of the polygon with vertices (1, 2) (1, -5) (5, -5) (5,2)
Svetradugi [14.3K]

Answer:

28 square units

Step-by-step explanation:

These vertices are written in the form of their x and y coordinates. Let

A=(1,2) ; B =(1,-5) ; C =(5, -5) ; D=(5,2)

The x points are 1, 1, 5, 5

The y points are 2,-5, -5, 2

The x extremes range from 1 to 5. The length  in-between is 5-1 = 4

The y extremes range from -5 to 2. The length  in-between is 2-(-5) = 7

Area of the polygon enclosed by the coordinates

   = 4 x 7 = 28 square units

5 0
3 years ago
Suppose that $1,000 is deposited into an account that yields
Lana71 [14]
ANSWER : $1,215.51

P= Principal = $1000
R= rate = 5% = 0.05
N= number or periods in 1 year (1 time pre year)
T= time expressed in years = 4 years

A= P (1 + r/n) nxt
= 1,000 (1+ 0.05/1) 1x4
= 1,215.51

6 0
4 years ago
A bag contains 6 blue counters and 4 red counters. I take two counters out at random. My
Step2247 [10]

Answer:

Possible outcome=6+4=10

P(red counter)=2/10=1/5

6 0
3 years ago
Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a
cluponka [151]

Answer:

B. Train B  

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

\text{Distance}=\text{Speed*Time}  

\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}

\text{Distance traveled by train A}=90\times 3{\text{ miles}

\text{Distance traveled by train A}=270{\text{ miles}

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}

\text{Distance traveled by train B}=70\times 5 \text{ miles}

\text{Distance traveled by train B}=350\text{ miles}  

Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.

5 0
4 years ago
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