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enot [183]
3 years ago
14

True or false, an equation with an integer coefficient will always have an integer solution.

Mathematics
2 answers:
Naily [24]3 years ago
6 0
False wanna know why?

x^2 - 2 = 2

has integer coefficients 
but the solutions are not integers
Sonja [21]3 years ago
5 0

Answer:

The statement is false.

Step-by-step explanation:

Consider the provided statement.

An equation with an integer coefficient will always have an integer solution.

Let's understand this with the help of an example:

x^2-3=0

Here the coefficient of x is an integer.

Now find the solution as shown.

x^2=3

x=\pm \sqrt{3}

Hence the solution for the equation is ±√3.

As we know √3 is an irrational number and it is not an integer,

Therefore, the above statement is false.

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When will these two lines intersect <br>C. y=-2x +3<br>y = x​
Andrej [43]

Answer:

The intersection point  of the given lines is  (1,1).

Step-by-step explanation:

Here, the given equations are:

y  =  - 2 x +  3

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Substitute y = x in  the first equation,

y   = -2 x  +  3 becomes      y =  -2 (y)  + 3

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Now, as x =  y ⇒ x =   1

Hence, the intersection points of the given lines is  (1,1).

8 0
3 years ago
If a gardner plants beans in 1/8 of a plot and tomatoes in 1/6 of a plot, what fraction of the garden is left for other crops
JulsSmile [24]

You simply have to sum the two fraction together to get the total amount of occupied plot. To do so, multiply both numerator and denominator of each fration by the same number, so that they end up having the same denominator.

You can multiply both numerator and denominator of 1/8 by 3 to get 3/24. Similarly, you can multiply both numerator and denominator of 1/6 by 4 to get 4/24.

Now we can easily sum the two fractions together:

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