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enot [183]
4 years ago
14

True or false, an equation with an integer coefficient will always have an integer solution.

Mathematics
2 answers:
Naily [24]4 years ago
6 0
False wanna know why?

x^2 - 2 = 2

has integer coefficients 
but the solutions are not integers
Sonja [21]4 years ago
5 0

Answer:

The statement is false.

Step-by-step explanation:

Consider the provided statement.

An equation with an integer coefficient will always have an integer solution.

Let's understand this with the help of an example:

x^2-3=0

Here the coefficient of x is an integer.

Now find the solution as shown.

x^2=3

x=\pm \sqrt{3}

Hence the solution for the equation is ±√3.

As we know √3 is an irrational number and it is not an integer,

Therefore, the above statement is false.

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Step-by-step explanation:

For any angle x (other than right angle) in a right triangle ,the trigonometric ratio of sin x is given by :-

\sin x=\frac{\text{side opposite to x}}{\text{Hypotenuse}}

Given: A right triangle with hypotenuse = 68 units

The side adjacent to S =  60

Let h be the side opposite to S, then using Pythagoras in the given right triangle, we get

(68)^2=60^2+h^2\\\\\Rightarrow\ h^2=68^2-60^2\\\\\Rightarrow\ h^2=1024\\\\\Rightarrow\ h=\sqrt{1024}=32

Thus, the side opposite to S = 32 units

Now,  the trigonometric ratio for sin S is given by :-

\sin S=\frac{\text{side opposite to S}}{\text{Hypotenuse}}\\\\\Rightarrow\sin S=\frac{32}{68}=\frac{8}{17}

Hence, the  trigonometric ratio for sin S =\frac{8}{17} or 8:17

5 0
3 years ago
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Step-by-step explanation:

(see attached)

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