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geniusboy [140]
3 years ago
13

The graph below shows the price of different numbers of beach balls at a store: Which equation can be used to determine p, the c

ost of b beach balls? b = 5.50p p = 5.50b p = 11b b = 11p

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

p = 5.50b

Step-by-step explanation:

2 beach balls cost 11

4 beach balls cost 22

6 beach balls cost 33

So each (1) ball b costs 5.50 ($) p

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Packet of 12 pencils = p
Packet of 30 rulers = r

p = £2.15
r = £6.00

£35 = 4r + xp
£35 = 4(£6.00) + x(£2.15)
£35 = £24 + £2.15x
£11 = £2.15x
x = 5.12

Since she can buy 5.12 packets of pencils, it is equal to 5 packets of pencils.
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The interquartile range of a data set is 10 units. What does this represent?
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About 3% of children in the United States are allergic to peanuts. Choose three children at random and let the random variable X
Charra [1.4K]

Answer:

0.029991 = 2.9991% conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are allergic to peanuts, or they are not. The probability of a children being allergic to peanut butter is independent of other children. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

3% of children in the United States are allergic to peanuts.

So p = 0.03

Three children:

So n = 3,

The probabilities are:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.03)^{0}.(0.97)^{3} = 0.912673

P(X = 1) = C_{3,1}.(0.03)^{1}.(0.97)^{2} = 0.084681

P(X = 2) = C_{3,2}.(0.03)^{2}.(0.97)^{1} = 0.002619

P(X = 3) = C_{3,3}.(0.03)^{3}.(0.97)^{0} = 0.000027

What is the conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy?

This is

p = \frac{P(X = 2)}{P(X \geq 1)}

In which

P(X \geq 1) = 0.084681 + 0.002619 + 0.000027 = 0.087327

P(X = 2) = 0.002619

So

p = \frac{0.002619}{0.087327} = 0.03

0.029991 = 2.9991% conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy

8 0
3 years ago
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