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Answer:
Step-by-step explanation:
Given ,
A right angle triangle ΔABC with right angle at C and ∠A=30° and AC=5√5 units .
Let ∠A=A,∠B=B∠C=C and AC=b,BC=a,CA=b .
Implies perimeter of triangle = a+b+c .
now
and
implies ,
The function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)
<h3>What is a function?</h3>It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have:
The graph of a function f(x) passes through the following points: (0,2), (1, 0), (-1,0)
Let
f(x) = ax² + bx + c
Plug x = 0, and y = 2
c = 2 ...(1)
Plug x = 1 and y = 0
a + b + c = 0 ..(2)
Plug x = -1 and y = 0
a - b + c = 0 ...(3)
After solving (1), (2), and (3)
a = -2
b = 0
c = 2
f(x) = -2x² + 2
Thus, the function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)
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