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3 years ago

Does this really works

Mathematics

1 answer:

Jet001 [13]3 years ago

7 0

Really works what..................................

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What is the least common multiple of 2, 6, 8, and 12?

Assoli18 [71]

24 because it’s the lowest multiple of 12 that’s also in 2,6 and 8

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3 years ago

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Suppose that the pages per book in a library are normally distributed with an unknown mean and standard deviation. The book leng

Elanso [62]

Answer:

A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 39 - 1 = 38

Now, we have to find a value of T, which is found looking at the t table, with 38 degrees of freedom(y-axis) and a confidence level of 0.99( $t_{99}$ ). So we have T = 2.0244.

A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean

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3 years ago

Need Help ASAP algebra 2

Anastasy [175]

Answer:

a = √10

Step-by-step explanation:

a² + b² = c²

a² + 9² = (√91)²

a² + 81 = 91

a² = 10

a = √10

hope this helps :)

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3 years ago

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Can someone please help?

puteri [66]

Answer:

1)Alternate exterior

2) corresponding

3) alternate interior

4) non of these

Mark me brainliest

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3 years ago

If cot theta= 4/3, find csc theta

Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

$csc^2\theta=cot^2\theta+1$

Knowing that $cot\theta=\frac{4}{3}$ :

Substitute it into $csc^2\theta=cot^2\theta+1$ :

$csc^2\theta=(\frac{4}{3})^2+1$

Simplify the expression:

$csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}$

Solve for $csc\theta$ . Apply square root at both sides of the expression:

$\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}$

$csc\theta=\frac{5}{3}$

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3 years ago