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3 years ago

Can anybody explain how I answer this question I really don't get trig equations

Mathematics

1 answer:

nasty-shy [4]3 years ago

6 0

SinØ(TanØ+2)=3cosØ -----[pulling like terms out]

for the following steps The easiest 4 me is that I just plug in values between 0° and 180° for Ø and see which will help me to get equal numbers on both sides.

So, for instance if you use Ø=90°, you'll get the following, Sin90(Tan90+2)=3cos90

========> 1(1+2)=3(1) ==> 3=3

so 90° is one of the solutions ur looking for.

hope this was helpful

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Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground

Scorpion4ik [409]

Answer:

$125.4\ \text{m/s}$

Step-by-step explanation:

u = Initial velocity of baseball

$\theta$ = Angle of hit = $30^{\circ}$

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

$y_0$ = Height of hit = 2.5 ft

$a_y$ = g = Acceleration due to gravity = $32.2\ \text{ft/s}^2$

t = Time taken

Displacement in x direction

$x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}$

Displacement in y direction

$y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}$

The minimum initial velocity needed for the ball to clear the fence is $125.4\ \text{m/s}$

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Step-by-step explanation:

x/3-7=11

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Check

54/3-7=11

18-7=11

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Read 2 more answers

Can anybody explain how I answer this question I really don't get trig equations ​

Can anybody explain how I answer this question I really don't get trig equations