All categories

2 years ago

Can anybody explain how I answer this question I really don't get trig equations

Mathematics

1 answer:

nasty-shy [4]2 years ago

6 0

SinØ(TanØ+2)=3cosØ -----[pulling like terms out]

for the following steps The easiest 4 me is that I just plug in values between 0° and 180° for Ø and see which will help me to get equal numbers on both sides.

So, for instance if you use Ø=90°, you'll get the following, Sin90(Tan90+2)=3cos90

========> 1(1+2)=3(1) ==> 3=3

so 90° is one of the solutions ur looking for.

hope this was helpful

You might be interested in

PlZZZ help picture attached

larisa86 [58]

1/2 divided by 1/6 is 3 or 3/1
you have to divide 2 to 6 and u get 3

4 0

3 years ago

Read 2 more answers

Jim has a membership to a comic book club. He pays $9.00 per month for membership and $2.50 for each comic book he purchases. Wh

tamaranim1 [39]

The answer is C) the slope is 2.50 and the y-intercept is 9, assuming the question refers to the parameters of his monthly cost.

His cost function could be described as y= 2.5x + 9, where x is the number of comic books he purchases. If he buys no comic books, he still has to pay the $9 membership fee.

8 0

3 years ago

Pls help im stuckkk ahhh

tangare [24]

B ^ 2, as its a tenth

6 0

3 years ago

Read 2 more answers

What is the surface area of a cube whose edges are 11 inches long?

Pepsi [2]

11 * 11 * 6 = 726 square inches

7 0

2 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

3 years ago

Can anybody explain how I answer this question I really don't get trig equations ​

Can anybody explain how I answer this question I really don't get trig equations