(a-b)^2 = a^2-2ab+b^2
(8-5i)^2 = 8^2-2(8)(5i)+(5i)^2
= 64-80i+25i^2
i^2=-1
So
= 64-80i+25(-1)
=64-25-80i
= <em><u>39 - 80i</u></em>
which is your answer :)
Answer:
θ ≈ 71.6°
Step-by-step explanation:
The angle between two lines with slopes m₁ and m₂ is:
tan θ = | (m₂ − m₁) / (1 + m₁m₂) |
Here, m₁ = -2 and m₂ = 1.
tan θ = | (1 − (-2)) / (1 + (-2)(1)) |
tan θ = | 3 / -1 |
tan θ = 3
θ ≈ 71.6°
What is it about. I think I can help you just got to explain what you need to do
