Answer: 2 buses and 4 vans would be needed
Step-by-step explanation:
Let x represent the number of buses that would be needed.
Let y represent the number of vans that would be needed.
There will be six drivers, and two different types of vehicles. This means that
x + y = 6
142 students are going on a field trip. A bus can hold 51 people while a van can hold 10. This means that
51x + 10y = 142 - - - - - - - - - - - 1
Substituting x = 6 - y into equation 1, it becomes
51(6 - y) + 10y = 142
306 - 51y + 10y = 142
- 51y + 10y = 142 - 306
- 41y = - 164
y = - 164/ - 41
y = 4
x = 6 - y = 6 - 4
x = 2
Answer:
The diagonals are congruent.
Step-by-step explanation:
Answer:
<h3>⇒ A. 2 should be distributed as 2y + 12, y = 6</h3>
Step-by-step explanation:
Here are the steps to solve this equation:
<u>Given:</u>
First step: 2(y+6)-4y
Use the distributive property.
<u>Distributive property:</u>
<h3>
⇒ A(B+C)=AB+AC</h3>
2(y+6)
2*y=2y
2*6=12
2y+12
Isolate the term of y from one side of the equations.
2y+12=4y
Subtract by 12 from both sides.
2y+12-12=4y-12
Solve.
2y=4y-12
Then, you subtract by 4y from both sides.
2y-4y=4y-12-4y
Solve.
2y-4y=-2y
-2y=-12
Divide by -2 from both sides.
Solve.
Divide the numbers from left to right.
<u>Solutions:</u>
-12/-2=6
- <u>Therefore, the correct answer is A. "2 should be distributed as 2y+12, y=6".</u>
I hope this helps. Let me know if you have any questions.
To answer the question above, calculate the price per ounce of cereal of each local grocery stores
Save-Some-More $0.33 / ounce
Save-The-Most $0.28 / ounce
Spend-Less-Money $0.27 / ounce
Cheap-Food $0.3 / ounce
Thus, the final arrangement should be: (1) Spend - Less-Money, (2) Save-The-Most, (3) Cheap-Food, (4) Save-Some-More
The first step for solving this inequality is to move the constant to the right side by adding its opposites to both sides. This will look like the following:
y - 6 + 6 ≥ 12 + 6
Eliminate the opposites on the left side.
y ≥ 12 + 6
Lastly,, add the numbers on the right side together to get your final answer.
y ≥ 18
Let me know if you have any further questions.
:)
