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3 years ago

9

Experimental probability is the same as empirical probability and relative frequency.

1 answer:

BlackZzzverrR [31]3 years ago

3 0

If this is a true or false question, then the answer would be true. It is correct that the three terms mentioned are the same. Experimental and empirical probability can be interchanged or even synonymous with one another, as well as relative frequency (or frequency ratio).

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4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (

Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

$\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408$

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0

2 years ago

A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa

Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion

p(private) be the proportion of alumni of the private university who attended at least one class reunion

Hypotheses are:

$H_{0}$ : p(public) = p(private)

$H_{a}$ : p(public) ≠ p(private)

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of public university students who attended at least one class reunion ( $\frac{808}{1311}=0.616$ )

p2 is the sample proportion of private university students who attended at least one class reunion ( $\frac{647}{1038}=0.623$ )

p is the pool proportion of p1 and p2 ( $\frac{808+647}{1311+1038}=0.619$ )

n1 is the sample size of the alumni from public university (1311)

n2 is the sample size of the students from private university (1038)

Then z= $\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}$ =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.

6 0

3 years ago

J PLS HELP 8 MINUTES LEFT Ted Thumper, who bats at number eight, had an average (mean) of 14 last year. So far this year he has

kotykmax [81]

Answer:

answer is 15 and second one i dont know yet sorry am doing scoo

Step-by-step explanation:

4 0

1 year ago

Which is equivalent to 5+2(3x-4)=12x-11? <br>C. 9x=17 <br>B. 6x=8 <br>D. 9x=-39

Rzqust [24]

5+2(3x-4)=12x-11 is 5+6x -8 = 12x -11, 5-8+11= 12x-6x, “8= 6x” so option B is correct

4 0

2 years ago

Read 2 more answers

Given g(x) = - 4x + 4, find g(3).<br> Answer:

likoan [24]

Answer:

-8

Step-by-step explanation:

substitute x with 3

-4(3) + 4

simplify (multiply)

-12+4

simplify

-8

4 0

2 years ago

Read 2 more answers